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2x^2+70x-2000=0
a = 2; b = 70; c = -2000;
Δ = b2-4ac
Δ = 702-4·2·(-2000)
Δ = 20900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{20900}=\sqrt{100*209}=\sqrt{100}*\sqrt{209}=10\sqrt{209}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-10\sqrt{209}}{2*2}=\frac{-70-10\sqrt{209}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+10\sqrt{209}}{2*2}=\frac{-70+10\sqrt{209}}{4} $
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